229. Majority Element II - LeetCode Solution


Array

Python Code:

class Solution:
    def majorityElement(self, nums: List[int]) -> List[int]:
        
        c = {}
        
        d = []
        
        for i in nums:
            if i in c:
                c[i] +=1
            else:
                c[i] = 1
                
                
        for i in c:
            if c[i] > len(nums)/3:
                d.append(i)
        
        return d


Comments

Submit
0 Comments
More Questions

1506D - Epic Transformation
1354G - Find a Gift
1426F - Number of Subsequences
1146B - Hate "A"
1718C - Tonya and Burenka-179
834A - The Useless Toy
1407D - Discrete Centrifugal Jumps
1095B - Array Stabilization
291B - Command Line Arguments
1174B - Ehab Is an Odd Person
624B - Making a String
1064C - Oh Those Palindromes
1471A - Strange Partition
1746A - Maxmina
1746B - Rebellion
66C - Petya and File System
1746C - Permutation Operations
1199B - Water Lily
570B - Simple Game
599C - Day at the Beach
862A - Mahmoud and Ehab and the MEX
1525A - Potion-making
1744D - Divisibility by 2n
1744A - Number Replacement
1744C - Traffic Light
1744B - Even-Odd Increments
637B - Chat Order
546C - Soldier and Cards
18D - Seller Bob
842B - Gleb And Pizza